Question

The angles of elevation of the top of a tower from two points at a distance of a and b (a > b) metres away from the base of the tower and in the same straight line with it are 30o and 60o respectively. Find the height of the tower.

Answer 1

Let the height of tower , AB be h metres .
Now ,
in △ABD ,
tan 60°=AB/BD
√3=h/b   ...(1)
In △ABC ,
tan 30°=AB/BC
1/√3=h/a
⇒ √3=a/h   ...(2)
From (1) and (2) , we get
h/b=a/h
h^2=ab
h=√ab metres .
Height of a tower is √ab metres .

Hope this information will clear your doubts about the topic .

Answer 2

Answer:

Check your answer please