The angles of elevation of the
top of a tower from two points
at a distance of 4 m and 9 m
from the base of the tower and
in the same straight line with
it are complementary. The
height of the tower is:
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Answer:
Let height of the tower be h m.
Given, the angles of elevation of the top of tower from the two points are complementary.
∴ ∠ACB = θ and ∠ADB = 90 – θ
In ∆ABC,
In ∆ABD,
∴ Height of the tower = h = 4 tan θ = 4 × = 6 m (Using (1))
Thus, the height of the tower is 6 m.
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