Question

The angles of elevation of the top of a tower from two points at distances of 5 metres and 20 metres from the base of the tower and in the same straight line with it, are complementary. Find the height of the tower.
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Answer 1

Answer:

MATE HERE IS YOUR ANSWER

BUT MAKE SURE YOU CHOOSE MY ANSWER AS BRAINLIEST ONE!!!

Step-by-step explanation:

THE DIAGRAM IS IN THE ABOVE PICTURE

From figure: Let θ be the angle of elevation.

Given: Angle are complementary, so another angle is (90- θ)°

From right triangle CAB: tan θ = AB/AC tan θ = h/5 or h = 5tan θ ….(1)

Form another right triangle DAB:

tan (90-θ)° = AB/AD tan (90-θ)° = h/20 or h = 20 tan (90-θ)° or h = 20 cot θ …(2)

Multiply equation (1) and (2), we get h2 = 100 x tan θ x cot θ h = 10 (As tan θ = 1/cotθ)

• Height of the tower is 10m

PLEASE DONT FORGET TO MARK MY ANSWER AS BRAINLIEST ONE!!!

BRAINLIEST ANSWER....

Answer 2

Answer:

hi frnd

good evening✨

have a great evening✨