Question

The angles of elevation of the top of a tower from two points at a distance of 4m and 9m from the base of the tower and in the same straight line with it are complementary. prove that the height of the tower is 6 m

Answer 1

$\tan\alpha = h \div 9 \\ \tan(90 - \alpha ) = h \div 4 \\ \cot( \alpha ) = h \div 4 \\ \tan( \alpha ) = 4 \div h$
So h=6m

Answer 2

hope it helps u.............