Question

The angles of elevation of the top of a tree 220 meters high from two points lie on the same plane are 30° and 45°. What is the distance (in metres) between the two points?

A) 193.22 B) 144.04 C) 176.12 D) 161.05

Answer 1

Answer:given that the height of the tower=220m

Now angle of elevations are 30°,45°

Tan 45°=220/x

220/x=1

x=220m

Tan 30°=220/x+220

1/√3=220/x+220

X=220(1.73-1)

X=220(0.73)

X=22×7.3=160.6m

Step-by-step explanation:

Hope u can understand it..