Math, asked by hsvaibhav25, 6 months ago

The angles of quadrilateral ABCD are in the ratio 3 : 5 : 9 : 13. Find the angles B of the quadrilateral.​

Answers

Answered by mahathivelu
3

Answer:

Let the angle of the quadrilateral ABCD be:

3x ; 5x ; 9x ; 13x

The sum of the quadrilateral = 360°

So,

⇒A + B + C + D = 360°

⇒3x + 5x + 9x + 13x = 360°

⇒30x = 360°

⇒x = \frac{360}{30}

x = 12°

Angle of A = 3 x 12 = 36°

Angle of  B = 5 X 12 = 60°

Angle of C = 9 x 12 = 108°

Angle of D = 13 x 12 = 156°

Hope it helps....

Answered by akashbindjnvg
0

Answer:

B=60°

Step-by-step explanation:

let the angle be 3x, 5x, 9x and 13x

A+B+C+D=360 (by angle sum property of qudrilateral)

3x+5x+9x13x=360

30x=360

x=360/30

x=12

so

b=5x=5×12=60°

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