Question

The Angles of quadrilateral are in A.P.
The Largest angle is 180. Find the
angle.
remaining​

Answer 1

The angles of a quadrilateral are in A.P. with a common difference of 20°. How do you find the angles?

First - Method:-

Let( a)°, (a+d)°,(a+2d)° and (a+3d)° are the

internal angles of a quadrilateral ABCD which are in A.P. and d=20°(given).

a+a+d+a+2d+a+3d=360°

4a+6d = 360° , put d=20°

4a+6×20° = 360°

4a = 360°-120°=240°

a = 240°/4= 60°

1st angle = a = 60°

2nd angle=a+d=60°+20°=80°

3rd angle=a+2d=60°+40°=100°

4th angle=a+3d=60°+60°=120°

60° , 80° , 100° , 120° . Answer.

Second-Method:-

Let first angle of a quadrilateral ABCD is a° then 2nd ,3rd and 4th angles shall be

(a+20)°, (a+40)° and (a+60)° respectively , accordingly:-

a+(a+20°)+(a+40°)+(a+60°)= 360°.

or. 4.a =360°- 120°= 240°

or. a= 240°/4 = 60°.

Thus , 1st angle = 60°.

2nd angle = a+20° =60°+20° = 80°.

3rd angle =a+40°=60°+40°= 100°.

4th angle =a+60° =60°+60°=120°. Answer.

HOPE IT'S HELPFUL....

Answer 2

Answer:

Let the angles be A and 2P

so

A+2P+180=360

A+2P+180=360

A+2P=360/180

A+2P=2

=4

180-4

176

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