Question

The angles of quadrilateral are in AP whose common difference is 10° find the angle

Answer 1

$\huge\boxed{answer}$

let the angles of the quadrilateral be X ,

X+10 . X+20 ,X+30

the sum of the angles of the

quadrilateral = 360 degrees

X+ X+ 10 + X+20 +X +30 = 360

====> 4X +60 = 360

==>4X = 360 - 60 = 300

====> X = 75

The angles of the quadrilateral are 75, 85, 95, 105 degrees

Answer 2

Answer:

Step-by-step explanation:

Let the angles be X(a), X + 10(a+d),X + 20(a+2d), X +30(a+3d).

Let us take the formula sn = n/2[2a + (n-1)d].

Let us substitute the values, to find the value of 'a'

360 = 4/2[2 x a + (4-1)10]

180 = 2a + 30

150 = 2a

a = 75°

a + d = 85°

a +2d = 95°

a + 3d = 105°

Thereforevthe angles are 75°,85°,95°,105°

Hope this helps!!!