The angles of quadrilateral are in ap whose common difference is 10 deg find angles
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suppose the angles are a,a+10,a+20,a+30
therefore a+a+10+a+20+a+30=360
=>4a+60=360
=>4a=300
=>a=75
the angles are 75,85,95,105
therefore a+a+10+a+20+a+30=360
=>4a+60=360
=>4a=300
=>a=75
the angles are 75,85,95,105
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