Question

The angles of quadrilateral are in the ratio 3:5:9:13. Find all
the angle of the quadrilateral.

​

Answer 1

Answer:

:5:9:13

⇒3x+5x+9x+13x

=360

50x=360

x=12

angle = 36∘

60∘

108∘

156∘

Answer 2

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Given :}}}}}}}$

$\sf{The \:angles \:in \: a \: quadrilateral \: are \:in \:the \: ratio \: 3:5:9:13}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{To\:Find :}}}}}}}$

$\sf{The \:measure \:of \:the \:angles}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Concept}}}}}}}$

$\sf{All \:the \:angles \:in \:a \: quadrilateral \:add \:upto \:360^0}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Solution}}}}}}}$

$\sf{Let \:the \:angles \:be \:3x, 5x, 9x \: and \:13x}$

$\sf{So,}$

$\sf{ 3x + 5x + 9x + 13x = 360^0}$

$\sf{30x = 360^0}$

$\sf{x = \dfrac {360^0}{30}}$

$\sf{x = 12^0}$

$\sf{So \:the \:angles \:are:}$

$\sf{3x = 3 \times 12 = 36^0}$

$\sf{5x = 5 \times 12 = 60^0}$

$\sf{9x = 9 \times 12 = 108^0}$

$\sf{13x = 13 \times 12 = 156^0}$