The angles of the depression from the top of a 60m high building to the base and top of a tower are 45°and 30° respectively.Find the height of the tower
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tan 45 and tan 60 than put tha ans
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rest here,
= 3 (60 – h) = 60
=180 – 3h) = 60
=180 – 60 = 3n
= 120 = 3h
=H-120/3
=h = 40
Thus, the height of the tower is 40 m.
HOPING IT WILL BE TO YOU
= 3 (60 – h) = 60
=180 – 3h) = 60
=180 – 60 = 3n
= 120 = 3h
=H-120/3
=h = 40
Thus, the height of the tower is 40 m.
HOPING IT WILL BE TO YOU
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