Question

the angles of the triangle are in the ratio 3:4:5.Find the smallest angle.​

Answer 1

Answer:

The ratio of angles of a triangle=3:4:5

Let the angle,

∠A,∠B and ∠C

then,

∠A:∠B:∠C=3:4:5

let the ratio=x

then,

∠A=3x,∠B=4x,∠C=5x

We know that,

∠A+∠B+∠C=180  

o

 

3x+4x+5x=180  

o

 

12x=180  

o

 

x=15  

o

 

then,

∠A=3x=3×15=45  

o

 

∠B=4x=4×15=60  

o

 

∠C=5x=5×15=75  

o

 

So, the smallest angle=∠A=45  

o

 

Hence, this is the answer.

Step-by-step explanation:

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Answer 2

Explanation

let the common ratio be x

let the common ratio be x

Angles of the triangle = 3x , 4x, 5x

According to the problem:3x + 4x + 5x = 180

12x = 180

x = 15

Angles = 45 , 60 , 75

Smallest angle is 45