Question

the angles of triangle are 2x, 3x and 5x. Find the value of x in degrees

Answer 1

GIVEN :-

• The angles of triangle are 2x, 3x and 5x.

TO FIND :-

• The value of x.

SOLUTION ;-

☯ The sum of angle of triangle is 180 °.

➬ 2x + 3x + 5x = 180°

➬ 10x = 180°

➬ x = 180/10

➬ x = 18°

Hence the value of x is 18°.

☯ Hence all the angles of Triangle,

1st angle:-

➫ 2x = 2 × 18

➫ 36°.

2nd angle:-

➫ 3x = 3 × 18

➫ 54°.

3rd angle:-

➫ 5x = 5 × 18

➫ 90°.

VERIFICATION :-

☯ The sum of angle of triangle is 180 °.

➬ 2x + 3x + 5x = 180°

➬ 36° + 54° + 90° = 180°

➬ 180° = 180°

L.H.S = R.H.S

HENCE VERIFIED ✔

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow angles\:of\:triangle\:are\:2x,3x\:and\:5x$

$\large\underline\bold{TO\:FIND,}$

$\sf\therefore VALUE\:OF\:"X"$

ACCORDING TO THE QUESTION,

✯PROPERTY IN USE,

$\sf\large\underline\bold{ANGLE\:SUM\:PROPERTY\:OF\:TRIANGLE\:[180 \degree]}$

$\large\underline\bold{SOLUTION,}$

USING ANGLE SUM PROPERTY,

$\sf\implies 2x + 3x + 5x = 180 \degree$

$\sf\implies 5x+5x=180\degree$

$\sf\implies 10x= 180\degree$

$\sf\implies x= \dfrac{180}{10}$

$\sf\implies x= \cancel \dfrac{180}{10}$

$\sf\implies x=18 \degree$

$\large{\boxed{\bf{ x=18\degree}}}$

$\sf\large\therefore NOW, \:FINDING\:THE\:VALUE\:OF\:OTHER\:TWO\:SIDES.$

$\sf\implies FOR,\:2x$

$\sf\therefore x=18\degree$

$\sf\implies 2 \times (18)$

$\sf\implies 36 \degree$

$\large{\boxed{\bf{ 2x=36\degree}}}$

$\sf\implies FOR,\:3x$

$\sf\therefore x=18\degree$

$\sf\implies 3 \times (18)$

$\sf\implies 54\degree$

$\large{\boxed{\bf{ 3x=54\degree}}}$

$\sf\implies FOR,\:5x$

$\sf\therefore x=18\degree$

$\sf\implies 5 \times (18)$

$\sf\implies 90 \degree$

$\large{\boxed{\bf{ 5x=90\degree}}}$

$\large\underline\bold{the\:value\:of\:x\:is\:18 \degree,}$

$\large\underline\bold{\therefore the\:angles\:of\:triangles\:are\:=36\degree ,54 \degree ,90 \degree}$

__________________________