The angles of triangle are in ap.if the smallest angle is 30 degree. Show that the triangle is right angle triangle
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let there is a difference of D in angles who are on ap.
first angle 30, second angle will be 30+D, third angle will be 30+2D
now adding these three angles will give 180 which is addition of all three angles of triangle.
hence 30+30+D+30+2D =180
90+3D= 180
3D= 180-90
3D=90
D= 90/3
D= 30
hence second angle will be 30+30=60
third Angle =30+2×30=90
since 90 is a right angle so it is right angle triangle.
first angle 30, second angle will be 30+D, third angle will be 30+2D
now adding these three angles will give 180 which is addition of all three angles of triangle.
hence 30+30+D+30+2D =180
90+3D= 180
3D= 180-90
3D=90
D= 90/3
D= 30
hence second angle will be 30+30=60
third Angle =30+2×30=90
since 90 is a right angle so it is right angle triangle.
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