The angles of triangle are in the ratio 4:1:1 then find the ratio of the longest side to the perimeter of triangle
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The angles of a triangle are in the ratio of 4:1:1, then the ratio of largest side to perimeter is:
The angles of the triangle are 120 : 30 : 30
We Know
a/ SinA = b/ SinB = c/ SinC = K
a = K SinA = K Sin120 = √ 3/2
b = K SinB = K Sin30 = 1/2
c = K SinC = K Sin30 = 1/2
the ratio of largest side to perimeter is √ 3/2 / (√ 3/2 + 1)
= √ 3/ (√ 3 + 2)
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The angles of the triangle are 120 : 30 : 30
We Know
a/ SinA = b/ SinB = c/ SinC = K
a = K SinA = K Sin120 = √ 3/2
b = K SinB = K Sin30 = 1/2
c = K SinC = K Sin30 = 1/2
the ratio of largest side to perimeter is √ 3/2 / (√ 3/2 + 1)
= √ 3/ (√ 3 + 2)
Hope it helps, if so please mark as brainliest.
Rhutik:
Answer Is √3/ √3+2
But you can see it clearly that both of us worked it out and we dot the same result.
yes ...ans is wrong...
my ans is also wrong...
OK I'll do something wait
I understand that iys the ratio of side..but have a look on ques...ratio of angle is given...
I will post correct ans...plss wait..
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