The angles of triangle are (X + 10) power 0 2 x minus 30 power zero and X power zero find the value of x
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Answered by
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Solution :
It may like this ,
( x + 10 )° , ( 2x - 30 )° , x° are angles
of the triangle.
Sum of the three angles = 180°
x + 10 + 2x - 30 + x = 180°
=> 4x - 20 = 180°
=> 4x = 180° + 20°
=> 4x = 200
=> x = 200/4
x = 50
Therefore ,
Required three angles are ,
x + 10 = 50° + 10 = 60°
2x - 30 = 2 × 50 - 30 = 100 - 30 = 70°
x = 50°
••••
It may like this ,
( x + 10 )° , ( 2x - 30 )° , x° are angles
of the triangle.
Sum of the three angles = 180°
x + 10 + 2x - 30 + x = 180°
=> 4x - 20 = 180°
=> 4x = 180° + 20°
=> 4x = 200
=> x = 200/4
x = 50
Therefore ,
Required three angles are ,
x + 10 = 50° + 10 = 60°
2x - 30 = 2 × 50 - 30 = 100 - 30 = 70°
x = 50°
••••
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1
Answer:
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