Question

The angles of triangle are (x + 10°), (2x – 30°) and x°. Find the value of x

(a) 30 (b) 50 (c) 60 (d) 40​

Answer 1

Given :

• Angles of triangle are (x + 10)° , (2x - 30)° and x°.

To Find :

• Value of x

Solution :

By Angle sum property of triangle.

⇒Sum of angles of Δ = 180°

⇒(x + 10)° + (2x - 30)° + x° = 180°

⇒x + 10 + 2x - 30 + x = 180°

⇒4x + 10 - 30 = 180°

⇒4x - 20 = 180°

⇒4x = 180 ° + 20°

⇒4x = 200°

⇒x = 200°/4

⇒x = 50°

∴ Value of x in 50°

$\rule{150}{2}$

Answer 2

Answer:

By the given condition

$x + 10^{\circ} + 2x - 30^{\circ} + x^{\circ} \: = 180^{\circ}$

$4x = 200^{\circ}$

$x = 50^{\circ}$

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