The angles of triangle are(x-40°),(x-20°)and(1/2x-10°)find the value x
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Here's your answer:-
(x - 40)° + (x - 20)° + (1/2x - 10)° = 180°
=> x - 40 + x - 20 + x/2 - 10 = 180
=> (2x - 80 + 2x - 40 + x - 20)/2 = 180
=> 5x - 140 = 180 × 2
=> 5x = 360 + 140
=> 5x = 500
=> x = 500/5
=> x = 100°
Thus, the value of x is 100°.
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MARK ME AS BRAINLIEST IF IT'S CORRECT^_^
Here's your answer:-
(x - 40)° + (x - 20)° + (1/2x - 10)° = 180°
=> x - 40 + x - 20 + x/2 - 10 = 180
=> (2x - 80 + 2x - 40 + x - 20)/2 = 180
=> 5x - 140 = 180 × 2
=> 5x = 360 + 140
=> 5x = 500
=> x = 500/5
=> x = 100°
Thus, the value of x is 100°.
HOPE IT HELPS
MARK ME AS BRAINLIEST IF IT'S CORRECT^_^
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