Question

the angles of triangles are x+10^0,2x-30^0 and x^0. find the value of x
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Answer 1

Hi there,

Angles of the triangle :

1st angle = (x-10)°

2nd angle = (2x-30)°

3rd angle = x°

Sum of interior angles in a triangle = (n-2)× 180° ,

where, n are the number of side,

so,

(3-2)× 180° = 180°

So,

the following equation will be formed,

x - 10 + 2x - 30 + x = 180

Regrouping the terms , we have,

x + 2x + x - 10 - 30 = 180

4x - 40 = 180

Transposing 40 to RHS,

we have,

4x = 180 + 40

4x = 220

x = 55

So,

1st angle = (x - 10)° = (55 -10)° = 45°

2nd angle = (2x - 30)° = 2 × 55 - 30 = 80°

3rd angle = x = 55°

Thus,

the angles are 45° , 80° and 55°

VERIFICATION:

Using angle sum property of a triangle, we know that the sum of angles should add up to 180°

So,

45° + 80° + 55° = 180°

Hence,

Our answer is correct !!

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