The angles which i^,j^,root 2 k makes with axis X Y Z are
manu9773:
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What is the meaning of cap
cap is ^ it is the way of reprentation of a unit vector like i^ here ^ is to be placed above the i
Can you please explain again how you got 2 and cos
becuase dot product of two vectors is equal to product of magnitude of two vectors and cos of the angle between them. that is A.i=|A||i|cosX
.magnitude of A = sqareroot(1+1+2) = sqareroot(4) = 2. A.i(on expanding) = i.i+i.j+i.sqareroot(2)k = 1+0+0 = 1. |i| = 1. therefore A.i =1 and |A|.|i| = 2. overall result will be
A.i=|A||i|cosX
=>1=2cosX
=>X=60⁰
.magnitude of A = sqareroot(1+1+2) = sqareroot(4) = 2. A.i(on expanding) = i.i+i.j+i.sqareroot(2)k = 1+0+0 = 1. |i| = 1. therefore A.i =1 and |A|.|i| = 2. overall result will be
A.i=|A||i|cosX
=>1=2cosX
=>X=60⁰
this is similarly with j and k
Thank you very much
But in case of k how you got root 2
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Let the unit vector along x axis be i(cap)
i+j+√2k=A is the given vector
A.i=|A||i|cosX
=>1=2cosX
=>X=60⁰ (angle made with the X axis)
Let the unit vector along y axis be j(cap)
A.j=|A||j|cosY
=>Y=60⁰ (angle made with the Y axis)
Let the unit vector along z axis be k(cap)
A.k=|A||k|cosZ
=>√2=2cosZ
=>Z=45⁰ (angle made with the Z axis)
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Answer:
Tis is also the solution
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