the anglesof a quadrilateralare in ratio 3:4:5:6.find all the four angles of the quadrilateral
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2
3x + 4x+ 5x + 6x = 360 degree
18x = 360
x = 360/18
= 20
so 1st angle 3*20 = 60
2nd angle 4 * 20 = 80
3rd angle 5* 20 = 100
4th angle 6 *20 = 120
18x = 360
x = 360/18
= 20
so 1st angle 3*20 = 60
2nd angle 4 * 20 = 80
3rd angle 5* 20 = 100
4th angle 6 *20 = 120
Answered by
1
Let assume all angles be x.
then,
∵ 3x, 4x, 5x, 6x
3x + 4x+ 5x + 6x = 360 degree (sum of all sides)
18x = 360
x = 360/18
= 20
∴first angle →3*20 = 60°
second angle →4 * 20 = 80°
third angle →5* 20 = 100°
fourth angle →6 *20 = 120°
then,
∵ 3x, 4x, 5x, 6x
3x + 4x+ 5x + 6x = 360 degree (sum of all sides)
18x = 360
x = 360/18
= 20
∴first angle →3*20 = 60°
second angle →4 * 20 = 80°
third angle →5* 20 = 100°
fourth angle →6 *20 = 120°
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