The anglle of elevation of the top of a building is found to be 60degree as messred from a point on the level ground, if the angle of elevation of a point on the building that is 3m below the top is 55 degree measured from the same point on the ground,then the height of the building is equal to
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Let the height of the tower =hm
and the distance between building and tower =xm
Now, in △AED,⇒tanx=
a60⇒atanx=60⟶(1)
Again, △BAC,⇒tanx= a(h−60)
⇒atanx=h−60⟶(2)
From equations (1)ξ(2), we get
⇒h−60=60
⇒h=120
∴ Height of tower 120m
Hence, the answer is 120.
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