The angry arjun carried some arrows for fighting with Bheeshm with half the arrows, he cut down the arrows thrown by Bheeshm on him and with six other arrows he killed the the charioteer of Bheeshm. with one arrows each he knocked down respectively the rath, flag and bow of Bheeshm. Finally, with one more than fours times the square root of arrows he laid Bheeshm unconscious on an arrows-bed. Find the total number of arrows Arjun had.
Answers
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Step-by-step explanation:
Let the number of arrows arjun had = 'x'.
(i)
Given that with half the arrows, he cut down the arrows thrown by Bheesm.
→ So, the number of arrows used to cut down the arrows of Bheesm = (x/2).
(ii)
Given that with six other arrows, he killed the rath driver of Bheesm.
→ So, the number of arrows used to kill the rath driver = 6.
(iii)
Given that one arrow each,he knocked down the rath,flag and bow of Bheesm.
→ So, the number of arrows used to knock rath,flag and bow = 3.
(iv)
Finally with one more than 4 times the square root of arrows he laid Bheesm unconscious.
→ 4√x + 1.
Now,
The total number of arrows carried by angry arjun :
→ x = (x/2) + 6 + 3 + 4√x + 1
→ 2x = x + 12 + 6 + 8√x + 2
→ 2x = x + 20 + 8√x
→ x = 20 + 8√x
→ x - 20 = 8√x
On squaring both sides, we get
→ (x - 20)^2 = (8√x)^2
→ x^2 + 400 - 40x = 64x
→ x^2 - 104x + 400 = 0
→ x^2 - 4x - 100x + 400 = 0
→ x(x - 4) - 100(x - 4) = 0
→ (x - 4)(x - 100) = 0
→ x = 100, 4{neglect - because he used more number of arrows}.
→ x = 100.
Therefore, the number of arrows Arjun had = 100.
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