The angry Arjun carried some arrows for fighting with Bheedhm.With half the arrows , he cut down the arrows thrown by Bheeshm on him and with six other arrows he killed the charioteer of Bheeshm.With one arrow each he knocked down respectively the rath,flag and bow of Bheeshm.Finally,with one more than four times the square root of arrows he laid Bheeshm unconscious on an arrow-bed.Find the total number of arrows Arjun had.
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Anonymous:
Answer is 100???
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Arjun had 100 arrows.
Answered by
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Hello user..It' s a really good question..
Here is a step by step explanation
The answer is..
Let the no. of arrows be x.
Therefore, arrows laid on Bheedm arrows = x/ 2
Arrows used by him to kill the charioter = 6
Arrows used in knocking down rath ,flag and bow of bheem = 3
now , atq
he laid one more than four times the square root .
therefore , arrows used : 1+√4*x/2
To sum up..
( x / 2)+6+3+1+√2x = x
(x + 12 +6+2+2√2x )= 2x
x + 20 + √4x = 2 x
x = 20 + √ 4 x
sq. both sides
x^2 = 400+4x +40√4x
....hope u can do further...
The answer would be 100 arrows ... according to me❤❤❤
Please mark it as a brainliest answer
Here is a step by step explanation
The answer is..
Let the no. of arrows be x.
Therefore, arrows laid on Bheedm arrows = x/ 2
Arrows used by him to kill the charioter = 6
Arrows used in knocking down rath ,flag and bow of bheem = 3
now , atq
he laid one more than four times the square root .
therefore , arrows used : 1+√4*x/2
To sum up..
( x / 2)+6+3+1+√2x = x
(x + 12 +6+2+2√2x )= 2x
x + 20 + √4x = 2 x
x = 20 + √ 4 x
sq. both sides
x^2 = 400+4x +40√4x
....hope u can do further...
The answer would be 100 arrows ... according to me❤❤❤
Please mark it as a brainliest answer
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