the angry arjun carries some arrows for fighting with bhism with half the arrows he cut down the arrows thrown by bhism on him and with 6 other arrows he killer the rath driver of bhism with one arrow each he knocked down respectively the rath flag and the bow of bhism finally with one more than four times the square roots of arrows he laid bhism unconscious on a arrow bed find the total number of arrows arjun had?
Answers
He used x/2 arrows to cut down Bheeshma arrows.
He used 6 arrows to kill the rath driver and another 3 for rath,flag and bow.
He used 4√3 + 1 arrows to put Bheesma on arrow bed.
From above, we have
x/2+6+3+4√3+1=x
=> x + 20 + 8√x= 2x
=> x-8√x-20=0
=>√x(√x-10)+2(√x-10)=0
=>(√x +2) (√x-10)=0
=> √x =10 or √x=100 (neglecting -tive value)
Therefore Arjun had 100 arrows.
Hope it helps u!
Step-by-step explanation:
Let the number of arrows arjun had = 'x'.
(i)
Given that with half the arrows, he cut down the arrows thrown by Bheesm.
→ So, the number of arrows used to cut down the arrows of Bheesm = (x/2).
(ii)
Given that with six other arrows, he killed the rath driver of Bheesm.
→ So, the number of arrows used to kill the rath driver = 6.
(iii)
Given that one arrow each,he knocked down the rath,flag and bow of Bheesm.
→ So, the number of arrows used to knock rath,flag and bow = 3.
(iv)
Finally with one more than 4 times the square root of arrows he laid Bheesm unconscious.
→ 4√x + 1.
Now,
The total number of arrows carried by angry arjun :
→ x = (x/2) + 6 + 3 + 4√x + 1
→ 2x = x + 12 + 6 + 8√x + 2
→ 2x = x + 20 + 8√x
→ x = 20 + 8√x
→ x - 20 = 8√x
On squaring both sides, we get
→ (x - 20)^2 = (8√x)^2
→ x^2 + 400 - 40x = 64x
→ x^2 - 104x + 400 = 0
→ x^2 - 4x - 100x + 400 = 0
→ x(x - 4) - 100(x - 4) = 0
→ (x - 4)(x - 100) = 0
→ x = 100, 4{neglect - because he used more number of arrows}.
→ x = 100.
Therefore, the number of arrows Arjun had = 100.
Hope it helps!