Question

. The angular displacement of a particle is given by the formula 2t^2 +5t -3

Derive an expression for the angular velocity?​

Answer 1

Answer:

angular velocity is equal to 4t+5.

Answer 2

☆point to note:

》differentiation of angular displacement($\theta$) with respect to time gives angular velocity($\omega$)

☆differentiation:

$\rightarrow{ \theta = 2t^{2} + 5t -3}$

$\rightarrow{ \dfrac{d\theta}{dt} = 2(2)t + 5}$

$\rightarrow{\bf{ \omega = 4t + 5}}$

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