The angular displacement of a particle moving along a circular path of radius r is 9π/2 rad. The displacement of the particle is
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1
Answer:
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A
2 r sin (θ/2)
The linear displacement,
△r
=
r
2
−
r
1
; where r
2
=r
1
=r
Hence, ∣△r∣=
r
2
2
+r
1
2
−2r
2
r
1
cosθ
⟹∣Δr∣=
2r
2
−2r
2
cosθ
⟹∣Δr∣=
2
r
1−cosθ
⟹∣Δr∣=2rsin(
2
θ
)
Explanation:
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Answered by
1
Answer:
The linear displacement,
△r
=
r
2
−
r
1
; where r
2
=r
1
=r
Hence, ∣△r∣=
r
2
2
+r
1
2
−2r
2
r
1
cosθ
⟹∣Δr∣=
2r
2
−2r
2
cosθ
⟹∣Δr∣=
2
r
1−cosθ
⟹∣Δr∣=2rsin(
2
θ
)
Explanation:
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