Question

•The angular momentum of a body is 24 kg-m^2/s & of rotation is 300 fi find its ahgulas speed and .m.I.​

Answer 1

Explanation:

Correct option is

C

4

ω=300rpm (given)

KE= 62.8 J (given)

L is angular momentum.

KE=

2

1

Iω

2

=

2

Lω

(conversion of energy in terms of angular momentum to see the variation of energy with respect to angular momentum)

62.8=

2

(L)

.

60

(300×2π)

L=4kgm

2

/s