Question

The angular momentum of a body rotating at the of 30 rpm about a given axis is kg m2

/s. Find the

rotational K.E.​

Answer 1

Answer:

ω=300rpm (given)

KE= 62.8 J (given)

L is angular momentum.

KE=

2

1

Iω

2

=

2

Lω

(conversion of energy in terms of angular momentum to see the variation of energy with respect to angular momentum)

62.8=

2

(L)

.

60

(300×2π)

L=4kgm

2

/s