Chemistry, asked by mdasadais, 11 months ago

The angular momentum of an electron in H-atom (according to Bohr's theory) present in the first excited state is:

Answers

Answered by kmswami2002
9

Answer:

Hi dude

Good Noon

Nice question

Explanation:

Angular Momentum,

L = 5.27 * 10⁻³⁴ kg m²/s

If it is helpful means just leave a thnks


iitaspirant52: wrong answer
kmswami2002: then give correct answer
Answered by AneesKakar
12

Answer:

Explanation:

As the question gives that the hydrogen ion is present in its 1st excited state so the value of n= 2 as the value of its energy must be -3.4ev.

Now to calculate the value of angular momentum L:-

L=mvr=nh/2pie

Here, n=2.

h= planks constant= 6.6*10^(-34)

Thus,

Angular momentum,

L= 2*6.6*10^(-34)/2*3.14

L=2.1*10^-34

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