Chemistry, asked by kalpanagupta402, 1 year ago

The angular momentum of electron in 'd' orbital is equal to :
(a) \sqrt{2} \hbar
(b) 2\sqrt{3} \hbar
(c) 0 \hbar
(d) \sqrt{6} \hbar

Answers

Answered by 99Abhi
0

answer is D

I hope u'll get it ..

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