Question

The angular momentum of electron in nth orbit is given by(a) nh(b) $\frac{h}{2\pi n}$(c) $n\frac{h}{2\pi}$(d) $n^{2}\frac{h}{2\pi}$

Answer 1

Answer:

B) nh/2π

Explanation:

The angular momentum of an electron by bohr is given by mvr or nh/2π where m is the mass of electron, v is the velocity, n is the orbit in which there is electron and r is the radius of the nth orbit.

According to bohr concept mvr = nh/2π and the angular acceleration of electron will be v²/r. The force will be mv²/r which will be equal to ze²/4π€r² where 1/4π€ will be constant. Thus the angular momentum is given by nh/2π.