Question

The angular momentum of electron in the shell in which the g-subshell first appears is x*h/2π.the value of x will be

Answer 1

Answer:

x=5

Explanation:

We have subshell numbered

s,p,d,f,g

1,2,3,4,5

Respectively

Angluar momentum=mvr=nh/2π

so therefore here x=n

n=no. of subshells

so in g subshell

n=5

so x=5

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Answer 2

The value of x will be $\sqrt{20}$

Explanation:

Orbital angular momentum is given by the formula given below:

$L=\sqrt{l(l+1)} \frac{h}{2 \pi}$

L = Orbital angular momentum

l = azimuthal quantum number

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-For l = 0,1,2,3... the orbitals are s, p, d, f.....

For a ‘g’ subshell, l = 4

Putting in the values, we get:

$L=\sqrt{4(4+1)}\frac{h}{2 \pi}=4.5\frac{h}{2 \pi}$

Thus the value of x is $\sqrt{20}$

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