Chemistry, asked by aaryaanafadnis, 9 months ago

The Angular momontum of the electron in the 2nd orbit is
(1) h/47
(2) h/2r
(3)2h/π
(4) h/π

Answers

Answered by Anonymous

1

Answer:

3 option is correct. support

Answered by shreyans1singhal

1

Answer:h/π

Explanation:

Orbital angular momentum i.e MVR = nh/2π

Where n = 2.

Therefore angular momentum = h/π

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