the angular position of a point at which electric field of an electric dipole is normal to its dipole moment vector is
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Answer:
(theta) =tan^-1((2)^(1/2))
Explanation:
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The value of the angular position is tanθ = √2
Explanation:
We are given that:
Dipole moment vector = r
Angle = θ
To find: the angular position of a point.
Solution:
As we know that:
θ + α makes 90 degree
θ + α = 90°
Now
2 tan α = tan θ
tan α = tan θ / 2
Tan ( 90 - θ) = tan θ / 2
Cot θ = tan θ / 2
[Since Cot θ = 1 / Tanθ ]
1 / Tanθ = tan θ / 2
tan^2θ = 2
Now taking under root on both sides of the euqtaion:
tanθ = √2
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