The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds. (i) What is its angular acceleration, (ii) How many revolutions does the engine make during this time?
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Answer:
use w1=w2+at
w1=initial angular speed
w2=final angular speed
w1=1200rpm=20rps
w2=3120rpm=52rps
52=20+a*16
a=2
then for no. of revolutions use s=w1t+(1/2)a*t^2
s=20*16+(1/2)*2*16^2
no. of revolutions = 576
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