Question

The angular speed of earth, so that the object on equator may appear weightless, is (g=10\,m/{{s}^{2}}
, radius of earth 6400 km) [Pb. PMT 2001]
A) 1.25\times {{10}^{-3}}rad/sec B) 1.56\times {{10}^{-3}}rad/sec C) 1.25\times {{10}^{-1}}rad/sec D) 1.56 rad/sec

Answer 1

for this
centrifugal acceleration = g
rw² = g
w = √(g/r)
w = √(10/6400000)
w = 1.25×10-³

ans is A)

Answer 2

The angular speed of earth, so that the object on equator may appear weightless, is (g=10\,m/{{s}^{2}}
, radius of earth 6400 km) [Pb. PMT 2001]
A) 1.25\times {{10}^{-3}}rad/sec B) 1.56\times {{10}^{-3}}rad/sec C) 1.25\times {{10}^{-1}}rad/sec D) 1.56 rad/sec