Question

The angular speed of motor wheel increased by 1200 rpm to 3120 rpm in 16 sec. what is its argular acceleration

Answer 1

Given:

Initial  angular speed= ωi=1200rpm=1200x 2π/60=7536/60=125.6rad/s²

final Angular speed= ωf =3120rpm=31200x2π/60=195936/60=3265.6rad/s²

time=t=16sec

Formula:

Angular acceleration=α= (ωf    -  ωi)/t

α =(3265.6-125.6)/16

=3140/16=196.25radians/s²