The angular speed of motor wheel is increased from 1200 RPM 3120 RPM in 16 seconds 1- what is its angular acceleration assuming acceleration to be uniform ?
2- how many Revolution does the wheel make during this time ?
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Answer:
ω
1
=1200rpm
=
60
1200×2π
=40πrad.s
−1
ω
2
=
60
3120×2π
=10πrad.s
−1
t=16sec
(1) Angular acceleration
a=
16
(ω
2
−ω
1
)
=
16
64π
=4πrad.s
−1
(2) Angle, θ =40π16+
2
1
(4π)×256
=1152rad.
(3) When there is no any external force applied on a system of partials then, momentum of system of particles will be consecrate or you can say that if external force is zero, then momentum of system of particles is initially = Momentum of system of particles is finally.
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