Question

The angular speed of motor wheel is increased from 1200 RPM 3120 RPM in 16 seconds 1- what is its angular acceleration assuming acceleration to be uniform ?
2- how many Revolution does the wheel make during this time ?​

Answer 1

Answer:

ω

1

=1200rpm

=

60

1200×2π

=40πrad.s

−1

ω

2

=

60

3120×2π

=10πrad.s

−1

t=16sec

(1) Angular acceleration

a=

16

(ω

2

−ω

1

)

=

16

64π

=4πrad.s

−1

(2) Angle, θ =40π16+

2

1

(4π)×256

=1152rad.

(3) When there is no any external force applied on a system of partials then, momentum of system of particles will be consecrate or you can say that if external force is zero, then momentum of system of particles is initially = Momentum of system of particles is finally.

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