Physics, asked by alifiashaikh2020, 8 months ago

The angular velocity and the amplitude of a simple pendulum is '' and a respectively. At a displacement x from the mean position if its kinetic energy is k and potential energy is p then the ratio of potential energy to kinetic energy is​

Answers

Answered by akashkumar02042001
1

Answer:

A simple harmonic oscillator will have equal KE and PE when its displacement from its central point is 0.707 of its amplitude (maximum displacement.) During simple harmonic motion, the energy goes back and forth between potential and kinetic energy.

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