The angular velocity of a particle moving along a
circle of radius 50 cm is increased in 5 minutes from
100 revolutions per minute to 400 revolutions per
minute. Find (i) angular acceleration and (ii) linear accelaration
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Answer:
r = 0.5m = 1÷2
t = 5min = 300sec
V1 = 2 pi × 400÷60
V2 = 2 pi × 100÷60
(i) Angular velocity = tv
V1 = 2 pi × 100÷120 = 15 pi ÷ 3
V2 = 2 pi × 400÷120 = 20 pi ÷ 3
A =V2 - V1 ÷ t
= (20pi ÷ 3 - 15pi ÷ 3) ÷ 300
= pi ÷ 60m/s^2
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