Question

The angular velocity of a particle moving in a circle of radius 50 cm is increased in 5 minute from 100 revolutions per minute to 400 revolutions per minute. Find tangential acceleration of the particle. 1) 60 m/s2 2) /30 m/s2 3) /15 m/s2 4) /60 m/s2

Answer 1

Answer:

Explanation:

R = 0.5m

t = 5 min

w1 = 100/min

w2 = 400/min

Angular acc = dw/dt = 300/5

                    = 60 revo/min²

                    = 60 x 2π/360  rad/s²

                    = 2π/60

Centri ac = v² /r

Tang Acc = rw = 0.5 x 2π/60

                = π/60

Answer 2

Answer:

Explanation:

Initial angular velocity of particle is ω1  =  200π /60  rads  −1

 

Final angular  velocity of particle is ω 2  =  800π /60  rads  −1

 angular acceleration α=   (ω  2  −ω  1) /T

​  

 where T is total time which is equal to 5×60=300sec

⇒α=(  800π /60 -200π/60 )/300

     =10π /300=π /30  rads  ^−2

​Tangential acceleration of the particle a=αr

where r is radius of the circle, r=  0.5m

⇒a=  π /30*1/2=π /60 ms ^−2

correct answer is D.

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