Question

The annual increase in population of a town is 5%. The increase in population from 1999 to 2000 is 8820. What was the population of the town in 1999​

Answer 1

Answer:

5% of 8820

=441

A.t.q

8820-441=8379

.

. . the population of town in 1999 is 8379.

Step-by-step explanation:

Answer 2

$5 \: \% \: of \: \: 8820 \\ = 441$

$A.T.Q$

$= 8820 - 441 \\ = 8379$

$population \: of \: the \: town \: \\ in \: 1999 \: \: is \: \:8379$