Math, asked by divija59, 6 days ago

The annual increase in population of a town was 10% increase in population from 2000 to 2003 was 6520 what was the population of the town in 2002 please tell I’ll mark as a brainlist

Answers

Answered by CarlyS
1

Answer:

Let the population of the town after 2 years be x

Increase percent of population every year = 10%

Present population = 180000

= 10% of 180000

= 10/100 * 180000 = 10*1800 = 18000

Increase in population after 1 year = 180000+18000 = 198000

Increase in population after 2 years = 10% of population in 1 year + population of 1 year

= 10% of 198000+198000

= 10/100 * 198000 = 10*1980 = 19800

= 198000+19800 = 217800

Therefore, the population of the town after 2 years is 217,800.

Hope this helps.

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