Question

the annual rate of growth in population in certain city is 8% if its present population is 196830 what it was 3 year ago​

Answer 1

The population of city 3 years ago is 153,269.

Answer 2

Answer:

$\begin{gathered}x(1 + \frac{8}{100} )^{3} = 196830 \\ or \: x \times ({ \frac{27}{25} })^{3} = 196830 \\ or \: x = 196830 \times \frac{25}{27} \times \frac{25}{27} \times \frac{25}{27} \\ or \: x = 10 \times 25 \times 25 \times 25 \\ or \: x = 156250\end{gathered} </p><p>x(1+ </p><p>100</p><p>8</p><p> </p><p> ) </p><p>3</p><p> =196830</p><p>orx×( </p><p>25</p><p>27</p><p> </p><p> ) </p><p>3</p><p> =196830</p><p>orx=196830× </p><p>27</p><p>25</p><p> </p><p> × </p><p>27</p><p>25</p><p> </p><p> × </p><p>27</p><p>25</p><p> </p><p> </p><p>orx=10×25×25×25$