Question

The annual rate of growth in population of a certain city is 8%. If its present population is 1,96,830, what was the population three years ago?​

Answer 1

$\frac{8}{100 \times} \times 196830 =$

Answer 2

Step-by-step explanation:

this question is like compound interest

therefore P=196830

r=8%

n=3years

a=p(1+r÷100)take power 3 because n=3 years