Question

. The annual rate of growth in population of a certain city is 8%. If its present
population is 1,96,830, what was the population three years ago?​

Answer 1

Answer:

so the annual rate of growth population of a certain city is 8% and its present population is 196830.

imagine 3 years ago the population was x.

so, According to the question...

\begin{gathered}x(1 + \frac{8}{100} )^{3} = 196830 \\ or \: x \times ({ \frac{27}{25} })^{3} = 196830 \\ or \: x = 196830 \times \frac{25}{27} \times \frac{25}{27} \times \frac{25}{27} \\ or \: x = 10 \times 25 \times 25 \times 25 \\ or \: x = 156250\end{gathered}

x(1+

100

8

)

3

=196830

orx×(

25

27

)

3

=196830

orx=196830×

27

25

×

27

25

×

27

25

orx=10×25×25×25

orx=156250

so three years ago the population was 156250

Answer 2

Explanation:

The annual rate of growth in population of a certain city is 8%. If its present

The annual rate of growth in population of a certain city is 8%. If its presentpopulation is 1,96,830, what was the population three years ago?

$x \times 2 = 2x$