the annual rate of growth in population of a certain city is 8%. If its present population is 1,96,830 what was the population 3 years ago?
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Answer: 247949
Step-by-step explanation:
After one year = 15746 + 196830 =212576
After second year = 17006 + 212576 = 229582
Final year = 18367 + 229582 = 247949
Note - every year the population in increase by 8 percent of present population in each case
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rudransh26:
can we do this sum by this method P(1+R/100)t
The formula for annual compound interest, including principal sum, is:
A = P (1 + r/n) (nt)
Where:
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the number of years the money is invested or borrowed for
A = P (1 + r/n) (nt)
Where:
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the number of years the money is invested or borrowed for
pls send replied
thank you
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Ok
ok <\br>
answer asked 3 years ago not after
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