Question

The annual rate of growth in population of a town is 10%. If its present popola 12
is 26620, the population 3 years ago was​

Answer 1

Answer:

Annual rate of population=10%

current population =26620

population 3 years ago = -30%

30% of 26620=7986

-30% of 26620 = 26620 - 7986

= 19134

so population 3 years ago = 19134

Answer 2

Answer:

The population would be 20,000

Step-by-step explanation:

Let P be the population before 3 years ago,

Since, the annual rate of increasing, r = 10% = 0.1,

Time, t = 3 years,

Thus, the current population,

$A=P(1+r)^t$

$=P(1+0.1)^3$

$=P(1.1)^3$

According to the question,

A = 26620,

$P(1.1)^3 = 26620$

$1.331P = 26620$

$\implies P =\frac{26620}{1.331}=20000$

Hence, the population before three years ago was 20,000

#Learn more :

The population of a country in 2009 was 120000.In the next year, it increased by 6% but due to epidemic, it decreased by 5%. What will be its population in 2011?

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