Question

The annual rate of growth in population of a town is 10%. If its present population is 33278
what was it 3 years ago?
(a) 25000 (b) 27500
(e) 30000
Idl 25000

pls answer step by step
and no useless comments on the questions☠​

Answer 1

Answer:

Answer:

25000

Step-by-step explanation:

Let x be the population 3 years ago

The annual rate of growth in population of a town is 10%

So, r = 10%

Formula : y=a(1+r)^ty=a(1+r)

t

y is the population after 3 years i.e. 33278

a is the initial population that is x

r = rate of growth = 0.1

33278=x(1+0.1)^333278=x(1+0.1)

3

x=25000x=25000

Hence the population 3 years ago was 25000

Answer 2

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$\large\sf{The \: Correct \: Answer \: Is } \: \: \bold {\underline { \red{ 25000}}} \: \: \: ☆ \: \:$

Answer :-

Given :

• The present population is 33,278 and the rate if growth is 10%.

To find :-

• the population 3 years ago.

The formula is :

• $\sf{A=P(1+r)^t}$

Here,

• A = final amount,
• P = initial amount,
• t = time,
• r = rate in decimal

Hence, we can find, P for

• A = 33,278

• t = 3

• r = 0.10

$\sf{Substituting \: these \: values \: in \: above \: formula \: : }$

$:{\implies}\sf{33,278 = P(1+0.10)^3}$

$\sf{:{\implies}P=\dfrac{33,278}{1(1+0.10)^{3}}}$

$\sf {</p><p> :{\implies}P=} \: \: \: \sf{ \underline{ \underline{ \red{25000}}} \: \bold{ \heartsuit}</p><p></p><p> }$

$☆⠀\small\sf { \underline{ \underline{ \green{Hence, \: the \: population \: three \: years \: ago \: was \: 25000.}}}}$

$\huge\bold {\underline { \red{ @Angel}}}$

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